8x^2+88x-12=0

Solution for 8x^2+88x-12=0 equation:

8x^2+88x-12=0

a = 8; b = 88; c = -12;
Δ = b2-4ac
Δ = 882-4·8·(-12)
Δ = 8128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8128}=\sqrt{64*127}=\sqrt{64}*\sqrt{127}=8\sqrt{127}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-8\sqrt{127}}{2*8}=\frac{-88-8\sqrt{127}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+8\sqrt{127}}{2*8}=\frac{-88+8\sqrt{127}}{16}
$